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13101200200201 = 44249929607299
BaseRepresentation
bin1011111010100101110001…
…1000100101001000001001
31201101110111011112100200111
42332221130120211020021
53204122224222401301
643510335220034321
72521346645201011
oct276513430451011
951343434470614
1013101200200201
1141a1207a68a93
1215771255329a1
1374059002c499
1433415c628c41
1517abd3e4b551
hexbea5c625209

13101200200201 has 4 divisors (see below), whose sum is σ = 13101230250000. Its totient is φ = 13101170150404.

The previous prime is 13101200200157. The next prime is 13101200200223. The reversal of 13101200200201 is 10200200210131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101200200201 - 223 = 13101191811593 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101200200261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14361151 + ... + 15246148.

It is an arithmetic number, because the mean of its divisors is an integer number (3275307562500).

Almost surely, 213101200200201 is an apocalyptic number.

It is an amenable number.

13101200200201 is a deficient number, since it is larger than the sum of its proper divisors (30049799).

13101200200201 is an equidigital number, since it uses as much as digits as its factorization.

13101200200201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30049798.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 13101200200201 its reverse (10200200210131), we get a palindrome (23301400410332).

The spelling of 13101200200201 in words is "thirteen trillion, one hundred one billion, two hundred million, two hundred thousand, two hundred one".

Divisors: 1 442499 29607299 13101200200201