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13101200200157 is a prime number
BaseRepresentation
bin1011111010100101110001…
…1000100101000111011101
31201101110111011112100121212
42332221130120211013131
53204122224222401112
643510335220034205
72521346645200616
oct276513430450735
951343434470555
1013101200200157
1141a1207a68a53
121577125532965
1374059002c464
1433415c628c0d
1517abd3e4b522
hexbea5c6251dd

13101200200157 has 2 divisors, whose sum is σ = 13101200200158. Its totient is φ = 13101200200156.

The previous prime is 13101200200139. The next prime is 13101200200223. The reversal of 13101200200157 is 75100200210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8227322725561 + 4873877474596 = 2868331^2 + 2207686^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101200200157 - 210 = 13101200199133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101200209157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550600100078 + 6550600100079.

It is an arithmetic number, because the mean of its divisors is an integer number (6550600100079).

Almost surely, 213101200200157 is an apocalyptic number.

It is an amenable number.

13101200200157 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101200200157 is an equidigital number, since it uses as much as digits as its factorization.

13101200200157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 23.

Adding to 13101200200157 its reverse (75100200210131), we get a palindrome (88201400410288).

The spelling of 13101200200157 in words is "thirteen trillion, one hundred one billion, two hundred million, two hundred thousand, one hundred fifty-seven".