Base | Representation |
---|---|
bin | 1011111010100101110001… |
… | …1000100101010111110011 |
3 | 1201101110111011112102001121 |
4 | 2332221130120211113303 |
5 | 3204122224222414303 |
6 | 43510335220043111 |
7 | 2521346645203642 |
oct | 276513430452763 |
9 | 51343434472047 |
10 | 13101200201203 |
11 | 41a1207a69814 |
12 | 1577125533497 |
13 | 74059002ca8a |
14 | 33415c629359 |
15 | 17abd3e4b9bd |
hex | bea5c6255f3 |
13101200201203 has 2 divisors, whose sum is σ = 13101200201204. Its totient is φ = 13101200201202.
The previous prime is 13101200201183. The next prime is 13101200201207. The reversal of 13101200201203 is 30210200210131.
It is a strong prime.
It is an emirp because it is prime and its reverse (30210200210131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13101200201203 - 241 = 10902176945651 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101200201207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550600100601 + 6550600100602.
It is an arithmetic number, because the mean of its divisors is an integer number (6550600100602).
Almost surely, 213101200201203 is an apocalyptic number.
13101200201203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101200201203 is an equidigital number, since it uses as much as digits as its factorization.
13101200201203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13101200201203 its reverse (30210200210131), we get a palindrome (43311400411334).
The spelling of 13101200201203 in words is "thirteen trillion, one hundred one billion, two hundred million, two hundred one thousand, two hundred three".
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