Base | Representation |
---|---|
bin | 11000011001110010… |
… | …00111011011010011 |
3 | 1020211001012222021122 |
4 | 30030321013123103 |
5 | 203312401413412 |
6 | 10004004112455 |
7 | 642442241411 |
oct | 141471073323 |
9 | 36731188248 |
10 | 13101201107 |
11 | 5613317335 |
12 | 265769572b |
13 | 130a346107 |
14 | 8c3d902b1 |
15 | 51a292572 |
hex | 30ce476d3 |
13101201107 has 2 divisors, whose sum is σ = 13101201108. Its totient is φ = 13101201106.
The previous prime is 13101201083. The next prime is 13101201173. The reversal of 13101201107 is 70110210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13101201107 - 210 = 13101200083 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101291107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550600553 + 6550600554.
It is an arithmetic number, because the mean of its divisors is an integer number (6550600554).
Almost surely, 213101201107 is an apocalyptic number.
13101201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101201107 is an equidigital number, since it uses as much as digits as its factorization.
13101201107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 17.
Adding to 13101201107 its reverse (70110210131), we get a palindrome (83211411238).
The spelling of 13101201107 in words is "thirteen billion, one hundred one million, two hundred one thousand, one hundred seven".
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