Base | Representation |
---|---|
bin | 11101110010011110011101… |
… | …000010001000100001100010 |
3 | 122011212121221001222012101122 |
4 | 131302132131002020201202 |
5 | 114133000110113341002 |
6 | 1142350031513532242 |
7 | 36411210015653255 |
oct | 3562363502104142 |
9 | 564777831865348 |
10 | 131012022012002 |
11 | 38820982a4972a |
12 | 1283b011114082 |
13 | 58144c44216a1 |
14 | 244d03111309c |
15 | 1022dcb47c6a2 |
hex | 77279d088862 |
131012022012002 has 4 divisors (see below), whose sum is σ = 196518033018006. Its totient is φ = 65506011006000.
The previous prime is 131012022011977. The next prime is 131012022012049. The reversal of 131012022012002 is 200210220210131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 119765248200361 + 11246773811641 = 10943731^2 + 3353621^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32753005502999 + ... + 32753005503002.
Almost surely, 2131012022012002 is an apocalyptic number.
131012022012002 is a deficient number, since it is larger than the sum of its proper divisors (65506011006004).
131012022012002 is an equidigital number, since it uses as much as digits as its factorization.
131012022012002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65506011006003.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 131012022012002 its reverse (200210220210131), we get a palindrome (331222242222133).
The spelling of 131012022012002 in words is "one hundred thirty-one trillion, twelve billion, twenty-two million, twelve thousand, two".
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