Base | Representation |
---|---|
bin | 11101110010011110100100… |
… | …010001001111101101111101 |
3 | 122011212122020112102001211011 |
4 | 131302132210101033231331 |
5 | 114133000332203223031 |
6 | 1142350051531555221 |
7 | 36411213021604333 |
oct | 3562364421175575 |
9 | 564778215361734 |
10 | 131012143414141 |
11 | 38820a35528980 |
12 | 1283b0458bbb11 |
13 | 5814513619882 |
14 | 244d0432b5b53 |
15 | 1022dd6e5d6b1 |
hex | 7727a444fb7d |
131012143414141 has 32 divisors (see below), whose sum is σ = 151355444929920. Its totient is φ = 112271414169600.
The previous prime is 131012143414133. The next prime is 131012143414153. The reversal of 131012143414141 is 141414341210131.
It is a cyclic number.
It is not a de Polignac number, because 131012143414141 - 23 = 131012143414133 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131012143414171) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29194861 + ... + 33382093.
It is an arithmetic number, because the mean of its divisors is an integer number (4729857654060).
Almost surely, 2131012143414141 is an apocalyptic number.
131012143414141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131012143414141 is a deficient number, since it is larger than the sum of its proper divisors (20343301515779).
131012143414141 is a wasteful number, since it uses less digits than its factorization.
131012143414141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4189597.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 131012143414141 its reverse (141414341210131), we get a palindrome (272426484624272).
The spelling of 131012143414141 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-three million, four hundred fourteen thousand, one hundred forty-one".
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