Base | Representation |
---|---|
bin | 11101110010011110100111… |
… | …101001100100011100010011 |
3 | 122011212122101111010010120002 |
4 | 131302132213221210130103 |
5 | 114133000441212402011 |
6 | 1142350101315240215 |
7 | 36411214310610626 |
oct | 3562364751443423 |
9 | 564778344103502 |
10 | 131012200122131 |
11 | 38820a64540489 |
12 | 1283b0608a906b |
13 | 58145222b32b3 |
14 | 244d04aa37dbd |
15 | 1022ddbe10c3b |
hex | 7727a7a64713 |
131012200122131 has 2 divisors, whose sum is σ = 131012200122132. Its totient is φ = 131012200122130.
The previous prime is 131012200122121. The next prime is 131012200122173. The reversal of 131012200122131 is 131221002210131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131012200122131 is a prime.
It is a super-2 number, since 2×1310122001221312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131012200122121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506100061065 + 65506100061066.
It is an arithmetic number, because the mean of its divisors is an integer number (65506100061066).
Almost surely, 2131012200122131 is an apocalyptic number.
131012200122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012200122131 is an equidigital number, since it uses as much as digits as its factorization.
131012200122131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 131012200122131 its reverse (131221002210131), we get a palindrome (262233202332262).
The spelling of 131012200122131 in words is "one hundred thirty-one trillion, twelve billion, two hundred million, one hundred twenty-two thousand, one hundred thirty-one".
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