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131012200122131 is a prime number
BaseRepresentation
bin11101110010011110100111…
…101001100100011100010011
3122011212122101111010010120002
4131302132213221210130103
5114133000441212402011
61142350101315240215
736411214310610626
oct3562364751443423
9564778344103502
10131012200122131
1138820a64540489
121283b0608a906b
1358145222b32b3
14244d04aa37dbd
151022ddbe10c3b
hex7727a7a64713

131012200122131 has 2 divisors, whose sum is σ = 131012200122132. Its totient is φ = 131012200122130.

The previous prime is 131012200122121. The next prime is 131012200122173. The reversal of 131012200122131 is 131221002210131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131012200122131 is a prime.

It is a super-2 number, since 2×1310122001221312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131012200122121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506100061065 + 65506100061066.

It is an arithmetic number, because the mean of its divisors is an integer number (65506100061066).

Almost surely, 2131012200122131 is an apocalyptic number.

131012200122131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012200122131 is an equidigital number, since it uses as much as digits as its factorization.

131012200122131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 131012200122131 its reverse (131221002210131), we get a palindrome (262233202332262).

The spelling of 131012200122131 in words is "one hundred thirty-one trillion, twelve billion, two hundred million, one hundred twenty-two thousand, one hundred thirty-one".