Base | Representation |
---|---|
bin | 11101110010011110100111… |
… | …101101101110000110000011 |
3 | 122011212122101120011102011112 |
4 | 131302132213231232012003 |
5 | 114133000442002211433 |
6 | 1142350101354433535 |
7 | 36411214323062153 |
oct | 3562364755560603 |
9 | 564778346142145 |
10 | 131012201210243 |
11 | 38820a65113a51 |
12 | 1283b0611328ab |
13 | 58145225a4652 |
14 | 244d04ac3c763 |
15 | 1022ddc078348 |
hex | 7727a7b6e183 |
131012201210243 has 2 divisors, whose sum is σ = 131012201210244. Its totient is φ = 131012201210242.
The previous prime is 131012201210221. The next prime is 131012201210309. The reversal of 131012201210243 is 342012102210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131012201210243 - 212 = 131012201206147 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012201215243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506100605121 + 65506100605122.
It is an arithmetic number, because the mean of its divisors is an integer number (65506100605122).
Almost surely, 2131012201210243 is an apocalyptic number.
131012201210243 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012201210243 is an equidigital number, since it uses as much as digits as its factorization.
131012201210243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 131012201210243 its reverse (342012102210131), we get a palindrome (473024303420374).
The spelling of 131012201210243 in words is "one hundred thirty-one trillion, twelve billion, two hundred one million, two hundred ten thousand, two hundred forty-three".
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