Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000101001000010101001010 |
3 | 122011212122110011021120020212 |
4 | 131302132221011020111022 |
5 | 114133001013333433414 |
6 | 1142350103533521122 |
7 | 36411215021615615 |
oct | 3562365105102512 |
9 | 564778404246225 |
10 | 131012224124234 |
11 | 38820a77044632 |
12 | 1283b0689431a2 |
13 | 581452726821b |
14 | 244d04dcc517c |
15 | 1022dde0a283e |
hex | 7727a914854a |
131012224124234 has 4 divisors (see below), whose sum is σ = 196518336186354. Its totient is φ = 65506112062116.
The previous prime is 131012224124129. The next prime is 131012224124269. The reversal of 131012224124234 is 432421422210131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 115745645005225 + 15266579119009 = 10758515^2 + 3907247^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 131012224124234.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32753056031057 + ... + 32753056031060.
Almost surely, 2131012224124234 is an apocalyptic number.
131012224124234 is a deficient number, since it is larger than the sum of its proper divisors (65506112062120).
131012224124234 is an equidigital number, since it uses as much as digits as its factorization.
131012224124234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65506112062119.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 131012224124234 its reverse (432421422210131), we get a palindrome (563433646334365).
The spelling of 131012224124234 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, one hundred twenty-four thousand, two hundred thirty-four".
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