Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000101011011101000101011 |
3 | 122011212122110011102120201111 |
4 | 131302132221011123220223 |
5 | 114133001013344001212 |
6 | 1142350103535331151 |
7 | 36411215022365266 |
oct | 3562365105335053 |
9 | 564778404376644 |
10 | 131012224203307 |
11 | 38820a77098a87 |
12 | 1283b068980ab7 |
13 | 5814527295205 |
14 | 244d04dd05cdd |
15 | 1022dde0baea7 |
hex | 7727a915ba2b |
131012224203307 has 2 divisors, whose sum is σ = 131012224203308. Its totient is φ = 131012224203306.
The previous prime is 131012224203271. The next prime is 131012224203317. The reversal of 131012224203307 is 703302422210131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131012224203307 is a prime.
It is not a weakly prime, because it can be changed into another prime (131012224203317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112101653 + 65506112101654.
It is an arithmetic number, because the mean of its divisors is an integer number (65506112101654).
Almost surely, 2131012224203307 is an apocalyptic number.
131012224203307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012224203307 is an equidigital number, since it uses as much as digits as its factorization.
131012224203307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 131012224203307 its reverse (703302422210131), we get a palindrome (834314646413438).
The spelling of 131012224203307 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred three thousand, three hundred seven".
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