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131012224204297 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000101011011111000001001
3122011212122110011102122002011
4131302132221011123320021
5114133001013344014142
61142350103535335521
736411215022401212
oct3562365105337011
9564778404378064
10131012224204297
1138820a770997a7
121283b0689815a1
1358145272957b7
14244d04dd06409
151022dde0bb417
hex7727a915be09

131012224204297 has 2 divisors, whose sum is σ = 131012224204298. Its totient is φ = 131012224204296.

The previous prime is 131012224204237. The next prime is 131012224204319. The reversal of 131012224204297 is 792402422210131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130925519868361 + 86704335936 = 11442269^2 + 294456^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131012224204297 is a prime.

It is a super-4 number, since 4×1310122242042974 (a number of 58 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (131012224204237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112102148 + 65506112102149.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112102149).

Almost surely, 2131012224204297 is an apocalyptic number.

It is an amenable number.

131012224204297 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224204297 is an equidigital number, since it uses as much as digits as its factorization.

131012224204297 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 40.

The spelling of 131012224204297 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred four thousand, two hundred ninety-seven".