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13101301209947 is a prime number
BaseRepresentation
bin1011111010100110001001…
…1001111001101101011011
31201101110202012121012000012
42332221202121321231123
53204122431102204242
643510353225032135
72521352312600036
oct276514231715533
951343665535005
1013101301209947
1141a1259a8a115
12157715332564b
137405a7c37772
1433416bc0001d
1517abdcc50282
hexbea62679b5b

13101301209947 has 2 divisors, whose sum is σ = 13101301209948. Its totient is φ = 13101301209946.

The previous prime is 13101301209889. The next prime is 13101301209959. The reversal of 13101301209947 is 74990210310131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13101301209947 - 222 = 13101297015643 is a prime.

It is not a weakly prime, because it can be changed into another prime (13101301209847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550650604973 + 6550650604974.

It is an arithmetic number, because the mean of its divisors is an integer number (6550650604974).

Almost surely, 213101301209947 is an apocalyptic number.

13101301209947 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101301209947 is an equidigital number, since it uses as much as digits as its factorization.

13101301209947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 41.

The spelling of 13101301209947 in words is "thirteen trillion, one hundred one billion, three hundred one million, two hundred nine thousand, nine hundred forty-seven".