Base | Representation |
---|---|
bin | 11101110010011111011000… |
… | …000111010011011011001011 |
3 | 122011212201111011002221102100 |
4 | 131302133120013103123023 |
5 | 114133004122341114430 |
6 | 1142350314123004443 |
7 | 36411243413060502 |
oct | 3562373007233313 |
9 | 564781434087370 |
10 | 131013013223115 |
11 | 3882134150a271 |
12 | 1283b249069723 |
13 | 58146218a233a |
14 | 244d0c6a13839 |
15 | 1022e384c4960 |
hex | 7727d81d36cb |
131013013223115 has 48 divisors (see below), whose sum is σ = 239216155027200. Its totient is φ = 66147623873856.
The previous prime is 131013013223041. The next prime is 131013013223149. The reversal of 131013013223115 is 511322310310131.
131013013223115 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 1 + 301 + 322 + 31 + 1 + 5 = 666.
It is not a de Polignac number, because 131013013223115 - 211 = 131013013221067 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 54877885 + ... + 57215454.
It is an arithmetic number, because the mean of its divisors is an integer number (4983669896400).
Almost surely, 2131013013223115 is an apocalyptic number.
131013013223115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131013013223115 is a deficient number, since it is larger than the sum of its proper divisors (108203141804085).
131013013223115 is a wasteful number, since it uses less digits than its factorization.
131013013223115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 112094736 (or 112094733 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 27.
Adding to 131013013223115 its reverse (511322310310131), we get a palindrome (642335323533246).
The spelling of 131013013223115 in words is "one hundred thirty-one trillion, thirteen billion, thirteen million, two hundred twenty-three thousand, one hundred fifteen".
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