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131013013223041 is a prime number
BaseRepresentation
bin11101110010011111011000…
…000111010011011010000001
3122011212201111011002221022121
4131302133120013103122001
5114133004122341114131
61142350314123004241
736411243413060335
oct3562373007233201
9564781434087277
10131013013223041
113882134150a204
121283b249069681
1358146218a22b1
14244d0c6a137c5
151022e384c4911
hex7727d81d3681

131013013223041 has 2 divisors, whose sum is σ = 131013013223042. Its totient is φ = 131013013223040.

The previous prime is 131013013223021. The next prime is 131013013223149. The reversal of 131013013223041 is 140322310310131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84171376854016 + 46841636369025 = 9174496^2 + 6844095^2 .

It is a cyclic number.

It is not a de Polignac number, because 131013013223041 - 221 = 131013011125889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131013013222997 and 131013013223015.

It is not a weakly prime, because it can be changed into another prime (131013013223021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506506611520 + 65506506611521.

It is an arithmetic number, because the mean of its divisors is an integer number (65506506611521).

Almost surely, 2131013013223041 is an apocalyptic number.

It is an amenable number.

131013013223041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131013013223041 is an equidigital number, since it uses as much as digits as its factorization.

131013013223041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131013013223041 its reverse (140322310310131), we get a palindrome (271335323533172).

The spelling of 131013013223041 in words is "one hundred thirty-one trillion, thirteen billion, thirteen million, two hundred twenty-three thousand, forty-one".