Base | Representation |
---|---|
bin | 1011111010100110001110… |
… | …1110001101101111110001 |
3 | 1201101110210202012002110221 |
4 | 2332221203232031233301 |
5 | 3204123002231441423 |
6 | 43510355334453041 |
7 | 2521353001502611 |
oct | 276514356155761 |
9 | 51343722162427 |
10 | 13101323312113 |
11 | 41a1270505873 |
12 | 157715a804181 |
13 | 7405ac6a597a |
14 | 334170b14a41 |
15 | 17abdeb68e5d |
hex | bea63b8dbf1 |
13101323312113 has 8 divisors (see below), whose sum is σ = 13480899141600. Its totient is φ = 12725151750528.
The previous prime is 13101323312093. The next prime is 13101323312117. The reversal of 13101323312113 is 31121332310131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13101323312113 - 213 = 13101323303921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13101323312117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 851059168 + ... + 851074561.
It is an arithmetic number, because the mean of its divisors is an integer number (1685112392700).
Almost surely, 213101323312113 is an apocalyptic number.
It is an amenable number.
13101323312113 is a deficient number, since it is larger than the sum of its proper divisors (379575829487).
13101323312113 is a wasteful number, since it uses less digits than its factorization.
13101323312113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1702133951.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 13101323312113 its reverse (31121332310131), we get a palindrome (44222655622244).
The spelling of 13101323312113 in words is "thirteen trillion, one hundred one billion, three hundred twenty-three million, three hundred twelve thousand, one hundred thirteen".
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