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131013402302 = 265506701151
BaseRepresentation
bin111101000000100000…
…0011101111010111110
3110112011112211102020102
41322001000131322332
54121303412333202
6140104155521102
712315430355006
oct1720100357276
9415145742212
10131013402302
11506207172a2
1221484159192
13c47bb25073
1464abd05006
15361bce0d02
hex1e8101debe

131013402302 has 4 divisors (see below), whose sum is σ = 196520103456. Its totient is φ = 65506701150.

The previous prime is 131013402281. The next prime is 131013402323. The reversal of 131013402302 is 203204310131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 203204310131 = 276773438493.

It is an interprime number because it is at equal distance from previous prime (131013402281) and next prime (131013402323).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32753350574 + ... + 32753350577.

It is an arithmetic number, because the mean of its divisors is an integer number (49130025864).

Almost surely, 2131013402302 is an apocalyptic number.

131013402302 is a deficient number, since it is larger than the sum of its proper divisors (65506701154).

131013402302 is an equidigital number, since it uses as much as digits as its factorization.

131013402302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65506701153.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131013402302 its reverse (203204310131), we get a palindrome (334217712433).

The spelling of 131013402302 in words is "one hundred thirty-one billion, thirteen million, four hundred two thousand, three hundred two".

Divisors: 1 2 65506701151 131013402302