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13101350330053 = 131100010307863
BaseRepresentation
bin1011111010100110010101…
…0101010001111011000101
31201101110212122000202010101
42332221211111101323011
53204123031141030203
643510402141524101
72521353450241246
oct276514525217305
951343778022111
1013101350330053
1141a1284789847
121577167873631
137405b517550b
14334174548ccd
1517abe220441d
hexbea65551ec5

13101350330053 has 4 divisors (see below), whose sum is σ = 13201360638048. Its totient is φ = 13001340022060.

The previous prime is 13101350330051. The next prime is 13101350330063. The reversal of 13101350330053 is 35003305310131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101350330053 - 21 = 13101350330051 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101350330051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50005153801 + ... + 50005154062.

It is an arithmetic number, because the mean of its divisors is an integer number (3300340159512).

Almost surely, 213101350330053 is an apocalyptic number.

It is an amenable number.

13101350330053 is a deficient number, since it is larger than the sum of its proper divisors (100010307995).

13101350330053 is a wasteful number, since it uses less digits than its factorization.

13101350330053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100010307994.

The product of its (nonzero) digits is 6075, while the sum is 28.

Adding to 13101350330053 its reverse (35003305310131), we get a palindrome (48104655640184).

The spelling of 13101350330053 in words is "thirteen trillion, one hundred one billion, three hundred fifty million, three hundred thirty thousand, fifty-three".

Divisors: 1 131 100010307863 13101350330053