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1310135517697 is a prime number
BaseRepresentation
bin10011000100001010001…
…010011000001000000001
311122020200121010002200111
4103010022022120020001
5132431124143031242
62441511250551321
7163440244104556
oct23041212301001
94566617102614
101310135517697
114656973876a6
12191ab5898541
1396711bb29a6
14475a7706a2d
152412db51817
hex1310a298201

1310135517697 has 2 divisors, whose sum is σ = 1310135517698. Its totient is φ = 1310135517696.

The previous prime is 1310135517641. The next prime is 1310135517701. The reversal of 1310135517697 is 7967155310131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1016112384576 + 294023133121 = 1008024^2 + 542239^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310135517697 - 27 = 1310135517569 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1310135517697.

It is not a weakly prime, because it can be changed into another prime (1310135517997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655067758848 + 655067758849.

It is an arithmetic number, because the mean of its divisors is an integer number (655067758849).

Almost surely, 21310135517697 is an apocalyptic number.

It is an amenable number.

1310135517697 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310135517697 is an equidigital number, since it uses as much as digits as its factorization.

1310135517697 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 595350, while the sum is 49.

The spelling of 1310135517697 in words is "one trillion, three hundred ten billion, one hundred thirty-five million, five hundred seventeen thousand, six hundred ninety-seven".