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13101412403 is a prime number
BaseRepresentation
bin11000011001110011…
…11011000000110011
31020211001121201010102
430030321323000303
5203312430144103
610004012423015
7642444111422
oct141471730063
936731551112
1013101412403
115613451062
122657777a6b
13130a3bb341
148c40072b9
1551a2d4e88
hex30ce7b033

13101412403 has 2 divisors, whose sum is σ = 13101412404. Its totient is φ = 13101412402.

The previous prime is 13101412343. The next prime is 13101412453. The reversal of 13101412403 is 30421410131.

13101412403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13101412403 - 214 = 13101396019 is a prime.

It is not a weakly prime, because it can be changed into another prime (13101412453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550706201 + 6550706202.

It is an arithmetic number, because the mean of its divisors is an integer number (6550706202).

Almost surely, 213101412403 is an apocalyptic number.

13101412403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101412403 is an equidigital number, since it uses as much as digits as its factorization.

13101412403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13101412403 its reverse (30421410131), we get a palindrome (43522822534).

The spelling of 13101412403 in words is "thirteen billion, one hundred one million, four hundred twelve thousand, four hundred three".