Base | Representation |
---|---|
bin | 111101000000100001… |
… | …1100001100000110010 |
3 | 110112011121100010012021 |
4 | 1322001003201200302 |
5 | 4121304114002232 |
6 | 140104225022054 |
7 | 12315440232463 |
oct | 1720103414062 |
9 | 415147303167 |
10 | 131014203442 |
11 | 506211141a1 |
12 | 2148448492a |
13 | c47c045905 |
14 | 64ac072d6a |
15 | 361bded397 |
hex | 1e810e1832 |
131014203442 has 4 divisors (see below), whose sum is σ = 196521305166. Its totient is φ = 65507101720.
The previous prime is 131014203407. The next prime is 131014203449. The reversal of 131014203442 is 244302410131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 98408317401 + 32605886041 = 313701^2 + 180571^2 .
It is not an unprimeable number, because it can be changed into a prime (131014203449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32753550859 + ... + 32753550862.
Almost surely, 2131014203442 is an apocalyptic number.
131014203442 is a deficient number, since it is larger than the sum of its proper divisors (65507101724).
131014203442 is an equidigital number, since it uses as much as digits as its factorization.
131014203442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65507101723.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 131014203442 its reverse (244302410131), we get a palindrome (375316613573).
The spelling of 131014203442 in words is "one hundred thirty-one billion, fourteen million, two hundred three thousand, four hundred forty-two".
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