Base | Representation |
---|---|
bin | 1011111010100111011101… |
… | …1101000010001000111100 |
3 | 1201101111122211002200102221 |
4 | 2332221313131002020330 |
5 | 3204124142003234234 |
6 | 43510452242055124 |
7 | 2521364131343020 |
oct | 276516735021074 |
9 | 51344584080387 |
10 | 13101654352444 |
11 | 41a1420360319 |
12 | 157723164a4a4 |
13 | 740633151118 |
14 | 3341a2a88380 |
15 | 17ac0dc59eb4 |
hex | bea7774223c |
13101654352444 has 12 divisors (see below), whose sum is σ = 26203308704944. Its totient is φ = 5614994722464.
The previous prime is 13101654352433. The next prime is 13101654352453. The reversal of 13101654352444 is 44425345610131.
13101654352444 is an admirable number.
It is a self number, because there is not a number n which added to its sum of digits gives 13101654352444.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233958113409 + ... + 233958113464.
Almost surely, 213101654352444 is an apocalyptic number.
13101654352444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13101654352444 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101654352444 is a wasteful number, since it uses less digits than its factorization.
13101654352444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 467916226884 (or 467916226882 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 43.
Adding to 13101654352444 its reverse (44425345610131), we get a palindrome (57526999962575).
The spelling of 13101654352444 in words is "thirteen trillion, one hundred one billion, six hundred fifty-four million, three hundred fifty-two thousand, four hundred forty-four".
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