1310202020213 has 8 divisors (see below), whose sum is σ = 1312177569120. Its totient is φ = 1308226702320.

The previous prime is 1310202020147. The next prime is 1310202020227. The reversal of 1310202020213 is 3120202020131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310202020213 - 2³² = 1305907052917 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1310202020191 and 1310202020200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310202020713) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13770518 + ... + 13865336.

It is an arithmetic number, because the mean of its divisors is an integer number (164022196140).

Almost surely, 2^{1310202020213} is an apocalyptic number.

It is an amenable number.

1310202020213 is a deficient number, since it is larger than the sum of its proper divisors (1975548907).

1310202020213 is an equidigital number, since it uses as much as digits as its factorization.

1310202020213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115507.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1310202020213 its reverse (3120202020131), we get a palindrome (4430404040344).

The spelling of 1310202020213 in words is "one trillion, three hundred ten billion, two hundred two million, twenty thousand, two hundred thirteen".