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1310202020713 is a prime number
BaseRepresentation
bin10011000100001110001…
…000000100001101101001
311122020212020020210200011
4103010032020010031221
5132431243204130323
62441522024211521
7163442012265115
oct23041610041551
94566766223604
101310202020713
1146572097a373
12191b14009ba1
13967228c88a1
14475b2498745
15241348db20d
hex1310e204369

1310202020713 has 2 divisors, whose sum is σ = 1310202020714. Its totient is φ = 1310202020712.

The previous prime is 1310202020689. The next prime is 1310202020737. The reversal of 1310202020713 is 3170202020131.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1310202020689) and next prime (1310202020737).

It can be written as a sum of positive squares in only one way, i.e., 766129082944 + 544072937769 = 875288^2 + 737613^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310202020713 - 225 = 1310168466281 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310202090713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655101010356 + 655101010357.

It is an arithmetic number, because the mean of its divisors is an integer number (655101010357).

Almost surely, 21310202020713 is an apocalyptic number.

It is an amenable number.

1310202020713 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310202020713 is an equidigital number, since it uses as much as digits as its factorization.

1310202020713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 22.

Adding to 1310202020713 its reverse (3170202020131), we get a palindrome (4480404040844).

The spelling of 1310202020713 in words is "one trillion, three hundred ten billion, two hundred two million, twenty thousand, seven hundred thirteen".