Base | Representation |
---|---|
bin | 10011000100001110001… |
… | …000000100001101101001 |
3 | 11122020212020020210200011 |
4 | 103010032020010031221 |
5 | 132431243204130323 |
6 | 2441522024211521 |
7 | 163442012265115 |
oct | 23041610041551 |
9 | 4566766223604 |
10 | 1310202020713 |
11 | 46572097a373 |
12 | 191b14009ba1 |
13 | 967228c88a1 |
14 | 475b2498745 |
15 | 241348db20d |
hex | 1310e204369 |
1310202020713 has 2 divisors, whose sum is σ = 1310202020714. Its totient is φ = 1310202020712.
The previous prime is 1310202020689. The next prime is 1310202020737. The reversal of 1310202020713 is 3170202020131.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (1310202020689) and next prime (1310202020737).
It can be written as a sum of positive squares in only one way, i.e., 766129082944 + 544072937769 = 875288^2 + 737613^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310202020713 - 225 = 1310168466281 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310202090713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655101010356 + 655101010357.
It is an arithmetic number, because the mean of its divisors is an integer number (655101010357).
Almost surely, 21310202020713 is an apocalyptic number.
It is an amenable number.
1310202020713 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310202020713 is an equidigital number, since it uses as much as digits as its factorization.
1310202020713 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 1310202020713 its reverse (3170202020131), we get a palindrome (4480404040844).
The spelling of 1310202020713 in words is "one trillion, three hundred ten billion, two hundred two million, twenty thousand, seven hundred thirteen".
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