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131020224410434 = 265510112205217
BaseRepresentation
bin11101110010100110000101…
…111011110011001101000010
3122011220102002201020012202011
4131302212011323303031002
5114133113404422113214
61142353505443443134
736411620205130312
oct3562460573631502
9564812081205664
10131020224410434
1138824401a98007
12128407200864aa
13581520087b698
14244d5ac625442
15102320b607ac4
hex772985ef3342

131020224410434 has 4 divisors (see below), whose sum is σ = 196530336615654. Its totient is φ = 65510112205216.

The previous prime is 131020224410429. The next prime is 131020224410447. The reversal of 131020224410434 is 434014422020131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 84445127496409 + 46575096914025 = 9189403^2 + 6824595^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131020224410396 and 131020224410405.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32755056102607 + ... + 32755056102610.

Almost surely, 2131020224410434 is an apocalyptic number.

131020224410434 is a deficient number, since it is larger than the sum of its proper divisors (65510112205220).

131020224410434 is an equidigital number, since it uses as much as digits as its factorization.

131020224410434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65510112205219.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 131020224410434 its reverse (434014422020131), we get a palindrome (565034646430565).

The spelling of 131020224410434 in words is "one hundred thirty-one trillion, twenty billion, two hundred twenty-four million, four hundred ten thousand, four hundred thirty-four".

Divisors: 1 2 65510112205217 131020224410434