Base | Representation |
---|---|
bin | 11101110010100110000101… |
… | …111011110011011011010011 |
3 | 122011220102002201020020222222 |
4 | 131302212011323303123103 |
5 | 114133113404422130342 |
6 | 1142353505443451255 |
7 | 36411620205133055 |
oct | 3562460573633323 |
9 | 564812081206888 |
10 | 131020224411347 |
11 | 38824401a98767 |
12 | 12840720086b2b |
13 | 581520087bc1b |
14 | 244d5ac6258d5 |
15 | 102320b607ed2 |
hex | 772985ef36d3 |
131020224411347 has 2 divisors, whose sum is σ = 131020224411348. Its totient is φ = 131020224411346.
The previous prime is 131020224411343. The next prime is 131020224411389. The reversal of 131020224411347 is 743114422020131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131020224411347 - 22 = 131020224411343 is a prime.
It is not a weakly prime, because it can be changed into another prime (131020224411343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510112205673 + 65510112205674.
It is an arithmetic number, because the mean of its divisors is an integer number (65510112205674).
Almost surely, 2131020224411347 is an apocalyptic number.
131020224411347 is a deficient number, since it is larger than the sum of its proper divisors (1).
131020224411347 is an equidigital number, since it uses as much as digits as its factorization.
131020224411347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 131020224411347 its reverse (743114422020131), we get a palindrome (874134646431478).
The spelling of 131020224411347 in words is "one hundred thirty-one trillion, twenty billion, two hundred twenty-four million, four hundred eleven thousand, three hundred forty-seven".
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