13102023113 has 2 divisors, whose sum is σ = 13102023114. Its totient is φ = 13102023112.

The previous prime is 13102023079. The next prime is 13102023119. The reversal of 13102023113 is 31132020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11272493584 + 1829529529 = 106172^2 + 42773^2 .

It is a cyclic number.

It is not a de Polignac number, because 13102023113 - 2⁶ = 13102023049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13102023091 and 13102023100.

It is not a weakly prime, because it can be changed into another prime (13102023119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551011556 + 6551011557.

It is an arithmetic number, because the mean of its divisors is an integer number (6551011557).

Almost surely, 2^13102023113 is an apocalyptic number.

It is an amenable number.

13102023113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102023113 is an equidigital number, since it uses as much as digits as its factorization.

13102023113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13102023113 its reverse (31132020131), we get a palindrome (44234043244).

The spelling of 13102023113 in words is "thirteen billion, one hundred two million, twenty-three thousand, one hundred thirteen".