Base | Representation |
---|---|
bin | 1011111010101000110101… |
… | …1011110100000010111010 |
3 | 1201101112121112000120221220 |
4 | 2332222031123310002322 |
5 | 3204130420410200242 |
6 | 43510553014212510 |
7 | 2521406230042056 |
oct | 276521533640272 |
9 | 51345545016856 |
10 | 13102023131322 |
11 | 41a159a541354 |
12 | 1577315054136 |
13 | 740691680988 |
14 | 3341d9a42c66 |
15 | 17ac31302bec |
hex | bea8d6f40ba |
13102023131322 has 16 divisors (see below), whose sum is σ = 27049338077952. Its totient is φ = 4226459074560.
The previous prime is 13102023131321. The next prime is 13102023131387. The reversal of 13102023131322 is 22313132020131.
It is a junction number, because it is equal to n+sod(n) for n = 13102023131292 and 13102023131301.
It is not an unprimeable number, because it can be changed into a prime (13102023131321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35220492103 + ... + 35220492474.
It is an arithmetic number, because the mean of its divisors is an integer number (1690583629872).
Almost surely, 213102023131322 is an apocalyptic number.
13102023131322 is an abundant number, since it is smaller than the sum of its proper divisors (13947314946630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102023131322 is a wasteful number, since it uses less digits than its factorization.
13102023131322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70440984613.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13102023131322 its reverse (22313132020131), we get a palindrome (35415155151453).
The spelling of 13102023131322 in words is "thirteen trillion, one hundred two billion, twenty-three million, one hundred thirty-one thousand, three hundred twenty-two".
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