Base | Representation |
---|---|
bin | 1011111010101000110101… |
… | …1011110100010000111111 |
3 | 1201101112121112000122012021 |
4 | 2332222031123310100333 |
5 | 3204130420410212343 |
6 | 43510553014221011 |
7 | 2521406230044514 |
oct | 276521533642077 |
9 | 51345545018167 |
10 | 13102023132223 |
11 | 41a159a541aa3 |
12 | 1577315054767 |
13 | 7406916811cc |
14 | 3341d9a4330b |
15 | 17ac313030ed |
hex | bea8d6f443f |
13102023132223 has 4 divisors (see below), whose sum is σ = 13149322855000. Its totient is φ = 13054723409448.
The previous prime is 13102023132217. The next prime is 13102023132227. The reversal of 13102023132223 is 32223132020131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13102023132223 - 213 = 13102023124031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102023132227) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23649860973 + ... + 23649861526.
It is an arithmetic number, because the mean of its divisors is an integer number (3287330713750).
Almost surely, 213102023132223 is an apocalyptic number.
13102023132223 is a deficient number, since it is larger than the sum of its proper divisors (47299722777).
13102023132223 is an equidigital number, since it uses as much as digits as its factorization.
13102023132223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47299722776.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13102023132223 its reverse (32223132020131), we get a palindrome (45325155152354).
The spelling of 13102023132223 in words is "thirteen trillion, one hundred two billion, twenty-three million, one hundred thirty-two thousand, two hundred twenty-three".
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