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13102031031300 = 223252233140949921
BaseRepresentation
bin1011111010101000110111…
…1001111100110000000100
31201101112122001212221200200
42332222031321330300010
53204130424421000200
643510553455410500
72521406354144061
oct276521571746004
951345561787620
1013102031031300
1141a15a3a47762
121577317823a30
137406931b8713
143341daadbc68
1517ac31d63800
hexbea8de7cc04

13102031031300 has 432 divisors, whose sum is σ = 44344538434560. Its totient is φ = 3226189824000.

The previous prime is 13102031031281. The next prime is 13102031031319. The reversal of 13102031031300 is 313013020131.

It is a happy number.

13102031031300 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 20 + 310 + 31 + 300 = 666.

It is an interprime number because it is at equal distance from previous prime (13102031031281) and next prime (13102031031319).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 262430340 + ... + 262480260.

Almost surely, 213102031031300 is an apocalyptic number.

13102031031300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13102031031300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22172269217280).

13102031031300 is an abundant number, since it is smaller than the sum of its proper divisors (31242507403260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13102031031300 is a wasteful number, since it uses less digits than its factorization.

13102031031300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50404 (or 50394 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 13102031031300 its reverse (313013020131), we get a palindrome (13415044051431).

The spelling of 13102031031300 in words is "thirteen trillion, one hundred two billion, thirty-one million, thirty-one thousand, three hundred".