131020431401041 has 32 divisors (see below), whose sum is σ = 162788411681280. Its totient is φ = 102680530412544.

The previous prime is 131020431401039. The next prime is 131020431401059. The reversal of 131020431401041 is 140104134020131.

It is not a de Polignac number, because 131020431401041 - 2¹ = 131020431401039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131020431400997 and 131020431401015.

It is not an unprimeable number, because it can be changed into a prime (131020431401441) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11737875 + ... + 19995463.

It is an arithmetic number, because the mean of its divisors is an integer number (5087137865040).

Almost surely, 2^{131020431401041} is an apocalyptic number.

It is an amenable number.

131020431401041 is a deficient number, since it is larger than the sum of its proper divisors (31767980280239).

131020431401041 is a wasteful number, since it uses less digits than its factorization.

131020431401041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8259265.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131020431401041 its reverse (140104134020131), we get a palindrome (271124565421172).

The spelling of 131020431401041 in words is "one hundred thirty-one trillion, twenty billion, four hundred thirty-one million, four hundred one thousand, forty-one".