131020441444232 has 16 divisors (see below), whose sum is σ = 248195939335260. Its totient is φ = 64834857621504.

The previous prime is 131020441444171. The next prime is 131020441444273. The reversal of 131020441444232 is 232444144020131.

It can be written as a sum of positive squares in 2 ways, for example, as 127303697015236 + 3716744428996 = 11282894^2 + 1927886^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131020441444192 and 131020441444201.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84420386753 + ... + 84420388304.

Almost surely, 2^{131020441444232} is an apocalyptic number.

It is an amenable number.

131020441444232 is a deficient number, since it is larger than the sum of its proper divisors (117175497891028).

131020441444232 is a wasteful number, since it uses less digits than its factorization.

131020441444232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 168840775160 (or 168840775156 counting only the distinct ones).

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 131020441444232 its reverse (232444144020131), we get a palindrome (363464585464363).

The spelling of 131020441444232 in words is "one hundred thirty-one trillion, twenty billion, four hundred forty-one million, four hundred forty-four thousand, two hundred thirty-two".