13102044244035 has 32 divisors (see below), whose sum is σ = 21215502745920. Its totient is φ = 6904069767168.

The previous prime is 13102044244021. The next prime is 13102044244049. The reversal of 13102044244035 is 53044244020131.

13102044244035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13102044244021) and next prime (13102044244049).

It is not a de Polignac number, because 13102044244035 - 2³⁰ = 13100970502211 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13102044243987 and 13102044244005.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11654830 + ... + 12729459.

It is an arithmetic number, because the mean of its divisors is an integer number (662984460810).

Almost surely, 2^{13102044244035} is an apocalyptic number.

13102044244035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13102044244035 is a deficient number, since it is larger than the sum of its proper divisors (8113458501885).

13102044244035 is a wasteful number, since it uses less digits than its factorization.

13102044244035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24384727.

The product of its (nonzero) digits is 46080, while the sum is 33.

Adding to 13102044244035 its reverse (53044244020131), we get a palindrome (66146288264166).

The spelling of 13102044244035 in words is "thirteen trillion, one hundred two billion, forty-four million, two hundred forty-four thousand, thirty-five".