131020443102301 has 4 divisors (see below), whose sum is σ = 131020666396704. Its totient is φ = 131020219807900.

The previous prime is 131020443102271. The next prime is 131020443102331. The reversal of 131020443102301 is 103201344020131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (131020443102271) and next prime (131020443102331).

It is a cyclic number.

It is not a de Polignac number, because 131020443102301 - 2³¹ = 131018295618653 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131020443102331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110764735 + ... + 111941356.

It is an arithmetic number, because the mean of its divisors is an integer number (32755166599176).

Almost surely, 2^{131020443102301} is an apocalyptic number.

It is an amenable number.

131020443102301 is a deficient number, since it is larger than the sum of its proper divisors (223294403).

131020443102301 is an equidigital number, since it uses as much as digits as its factorization.

131020443102301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 223294402.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131020443102301 its reverse (103201344020131), we get a palindrome (234221787122432).

The spelling of 131020443102301 in words is "one hundred thirty-one trillion, twenty billion, four hundred forty-three million, one hundred two thousand, three hundred one".