Base | Representation |
---|---|
bin | 11101110010100110110100… |
… | …011001101101110000111011 |
3 | 122011220111010001011200122011 |
4 | 131302212310121231300323 |
5 | 114133122004011120121 |
6 | 1142354115053110351 |
7 | 36411645422434123 |
oct | 3562466431556073 |
9 | 564814101150564 |
10 | 131021004004411 |
11 | 38824772060554 |
12 | 128408b91883b7 |
13 | 58152c62383b1 |
14 | 244d643d9bc83 |
15 | 1023254c9d7e1 |
hex | 7729b466dc3b |
131021004004411 has 2 divisors, whose sum is σ = 131021004004412. Its totient is φ = 131021004004410.
The previous prime is 131021004004349. The next prime is 131021004004439. The reversal of 131021004004411 is 114400400120131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131021004004411 - 225 = 131020970449979 is a prime.
It is not a weakly prime, because it can be changed into another prime (131021104004411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510502002205 + 65510502002206.
It is an arithmetic number, because the mean of its divisors is an integer number (65510502002206).
Almost surely, 2131021004004411 is an apocalyptic number.
131021004004411 is a deficient number, since it is larger than the sum of its proper divisors (1).
131021004004411 is an equidigital number, since it uses as much as digits as its factorization.
131021004004411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 131021004004411 its reverse (114400400120131), we get a palindrome (245421404124542).
The spelling of 131021004004411 in words is "one hundred thirty-one trillion, twenty-one billion, four million, four thousand, four hundred eleven".
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