Base | Representation |
---|---|
bin | 111101000000101110… |
… | …1011111110011111011 |
3 | 110112012002011001002012 |
4 | 1322001131133303323 |
5 | 4121312334342334 |
6 | 140105031000135 |
7 | 12315552141236 |
oct | 1720135376373 |
9 | 415162131065 |
10 | 131021012219 |
11 | 50624a44789 |
12 | 2148680904b |
13 | c48058aa86 |
14 | 64acd2641d |
15 | 361c7e59ce |
hex | 1e8175fcfb |
131021012219 has 2 divisors, whose sum is σ = 131021012220. Its totient is φ = 131021012218.
The previous prime is 131021012207. The next prime is 131021012249. The reversal of 131021012219 is 912210120131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131021012219 - 220 = 131019963643 is a prime.
It is a super-2 number, since 2×1310210122192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131021012194 and 131021012203.
It is not a weakly prime, because it can be changed into another prime (131021012249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510506109 + 65510506110.
It is an arithmetic number, because the mean of its divisors is an integer number (65510506110).
Almost surely, 2131021012219 is an apocalyptic number.
131021012219 is a deficient number, since it is larger than the sum of its proper divisors (1).
131021012219 is an equidigital number, since it uses as much as digits as its factorization.
131021012219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 131021012219 in words is "one hundred thirty-one billion, twenty-one million, twelve thousand, two hundred nineteen".
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