Base | Representation |
---|---|
bin | 11101110010100110110100… |
… | …111001110100101000000000 |
3 | 122011220111010122000022012010 |
4 | 131302212310321310220000 |
5 | 114133122013134433440 |
6 | 1142354115553332520 |
7 | 36411645554120463 |
oct | 3562466471645000 |
9 | 564814118008163 |
10 | 131021012421120 |
11 | 3882477688a108 |
12 | 128408bbb67140 |
13 | 58152c7bc43b3 |
14 | 244d64514d2da |
15 | 10232558b2580 |
hex | 7729b4e74a00 |
131021012421120 has 320 divisors, whose sum is σ = 437132014260480. Its totient is φ = 33415034830848.
The previous prime is 131021012421107. The next prime is 131021012421161. The reversal of 131021012421120 is 21124210120131.
It is a tau number, because it is divible by the number of its divisors (320).
It is a super-3 number, since 3×1310210124211203 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1317154746 + ... + 1317254214.
It is an arithmetic number, because the mean of its divisors is an integer number (1366037544564).
Almost surely, 2131021012421120 is an apocalyptic number.
131021012421120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131021012421120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (218566007130240).
131021012421120 is an abundant number, since it is smaller than the sum of its proper divisors (306111001839360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131021012421120 is an equidigital number, since it uses as much as digits as its factorization.
131021012421120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106975 (or 106959 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 131021012421120 its reverse (21124210120131), we get a palindrome (152145222541251).
The spelling of 131021012421120 in words is "one hundred thirty-one trillion, twenty-one billion, twelve million, four hundred twenty-one thousand, one hundred twenty".
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