Base | Representation |
---|---|
bin | 11000011001111001… |
… | …00011101100000101 |
3 | 1020211002220210212020 |
4 | 30030330203230011 |
5 | 203313114301201 |
6 | 10004035313353 |
7 | 642453016620 |
oct | 141474435405 |
9 | 36732823766 |
10 | 13102103301 |
11 | 5613883151 |
12 | 2657a4b859 |
13 | 130a5a0961 |
14 | 8c4146db7 |
15 | 51a3bea36 |
hex | 30cf23b05 |
13102103301 has 16 divisors (see below), whose sum is σ = 20017250304. Its totient is φ = 7467363504.
The previous prime is 13102103297. The next prime is 13102103351. The reversal of 13102103301 is 10330120131.
It is not a de Polignac number, because 13102103301 - 22 = 13102103297 is a prime.
It is a super-2 number, since 2×131021033012 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102103351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 806461 + ... + 822546.
It is an arithmetic number, because the mean of its divisors is an integer number (1251078144).
Almost surely, 213102103301 is an apocalyptic number.
It is an amenable number.
13102103301 is a deficient number, since it is larger than the sum of its proper divisors (6915147003).
13102103301 is a wasteful number, since it uses less digits than its factorization.
13102103301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1629400.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13102103301 its reverse (10330120131), we get a palindrome (23432223432).
It can be divided in two parts, 13102 and 103301, that added together give a triangular number (116403 = T482).
The spelling of 13102103301 in words is "thirteen billion, one hundred two million, one hundred three thousand, three hundred one".
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