Base | Representation |
---|---|
bin | 11000011001111001… |
… | …00011101100110111 |
3 | 1020211002220210221002 |
4 | 30030330203230313 |
5 | 203313114301401 |
6 | 10004035313515 |
7 | 642453020021 |
oct | 141474435467 |
9 | 36732823832 |
10 | 13102103351 |
11 | 5613883197 |
12 | 2657a4b89b |
13 | 130a5a099c |
14 | 8c4147011 |
15 | 51a3bea6b |
hex | 30cf23b37 |
13102103351 has 2 divisors, whose sum is σ = 13102103352. Its totient is φ = 13102103350.
The previous prime is 13102103297. The next prime is 13102103389. The reversal of 13102103351 is 15330120131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13102103351 is a prime.
It is a super-2 number, since 2×131021033512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13102103551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551051675 + 6551051676.
It is an arithmetic number, because the mean of its divisors is an integer number (6551051676).
Almost surely, 213102103351 is an apocalyptic number.
13102103351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102103351 is an equidigital number, since it uses as much as digits as its factorization.
13102103351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 13102103351 its reverse (15330120131), we get a palindrome (28432223482).
The spelling of 13102103351 in words is "thirteen billion, one hundred two million, one hundred three thousand, three hundred fifty-one".
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