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13102110203302 = 26551055101651
BaseRepresentation
bin1011111010101001001010…
…0111111101110110100110
31201101112211120212022021001
42332222102213331312212
53204131110203001202
643511005404343514
72521411335121201
oct276522247756646
951345746768231
1013102110203302
1141a163470286a
12157733a244b9a
137406a6718c63
1433420742a938
1517ac38ca1d87
hexbea929fdda6

13102110203302 has 4 divisors (see below), whose sum is σ = 19653165304956. Its totient is φ = 6551055101650.

The previous prime is 13102110203293. The next prime is 13102110203311. The reversal of 13102110203302 is 20330201120131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13102110203293) and next prime (13102110203311).

It is a self number, because there is not a number n which added to its sum of digits gives 13102110203302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275527550824 + ... + 3275527550827.

It is an arithmetic number, because the mean of its divisors is an integer number (4913291326239).

Almost surely, 213102110203302 is an apocalyptic number.

13102110203302 is a deficient number, since it is larger than the sum of its proper divisors (6551055101654).

13102110203302 is an equidigital number, since it uses as much as digits as its factorization.

13102110203302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6551055101653.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13102110203302 its reverse (20330201120131), we get a palindrome (33432311323433).

The spelling of 13102110203302 in words is "thirteen trillion, one hundred two billion, one hundred ten million, two hundred three thousand, three hundred two".

Divisors: 1 2 6551055101651 13102110203302