13102111133233 has 8 divisors (see below), whose sum is σ = 13460452552040. Its totient is φ = 12743992362240.

The previous prime is 13102111133231. The next prime is 13102111133269. The reversal of 13102111133233 is 33233111120131.

13102111133233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 535490259984 + 12566620873249 = 731772^2 + 3544943^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13102111133233 - 2¹ = 13102111133231 is a prime.

It is a super-3 number, since 3×13102111133233³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13102111133198 and 13102111133207.

It is not an unprimeable number, because it can be changed into a prime (13102111133231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55542648 + ... + 55778041.

It is an arithmetic number, because the mean of its divisors is an integer number (1682556569005).

Almost surely, 2^{13102111133233} is an apocalyptic number.

It is an amenable number.

13102111133233 is a deficient number, since it is larger than the sum of its proper divisors (358341418807).

13102111133233 is a wasteful number, since it uses less digits than its factorization.

13102111133233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111323907.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13102111133233 its reverse (33233111120131), we get a palindrome (46335222253364).

The spelling of 13102111133233 in words is "thirteen trillion, one hundred two billion, one hundred eleven million, one hundred thirty-three thousand, two hundred thirty-three".