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13102111300200 = 23352132173746891
BaseRepresentation
bin1011111010101001001010…
…1100001001101001101000
31201101112211122221000220220
42332222102230021221220
53204131110443101300
643511005444050040
72521411350340146
oct276522254115150
951345748830826
1013102111300200
1141a163529199a
12157733a693920
137406a6a11300
14334207634596
1517ac38e1bda0
hexbea92b09a68

13102111300200 has 288 divisors, whose sum is σ = 44235515219040. Its totient is φ = 3206488396800.

The previous prime is 13102111300151. The next prime is 13102111300211. The reversal of 13102111300200 is 200311120131.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13102111300200.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 17168755 + ... + 17915645.

It is an arithmetic number, because the mean of its divisors is an integer number (153595538955).

Almost surely, 213102111300200 is an apocalyptic number.

13102111300200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13102111300200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22117757609520).

13102111300200 is an abundant number, since it is smaller than the sum of its proper divisors (31133403918840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13102111300200 is a wasteful number, since it uses less digits than its factorization.

13102111300200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 747109 (or 747087 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13102111300200 its reverse (200311120131), we get a palindrome (13302422420331).

The spelling of 13102111300200 in words is "thirteen trillion, one hundred two billion, one hundred eleven million, three hundred thousand, two hundred".