131021131027 has 2 divisors, whose sum is σ = 131021131028. Its totient is φ = 131021131026.

The previous prime is 131021130941. The next prime is 131021131037. The reversal of 131021131027 is 720131120131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131021131027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131021130989 and 131021131007.

It is not a weakly prime, because it can be changed into another prime (131021131037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510565513 + 65510565514.

It is an arithmetic number, because the mean of its divisors is an integer number (65510565514).

Almost surely, 2^131021131027 is an apocalyptic number.

131021131027 is a deficient number, since it is larger than the sum of its proper divisors (1).

131021131027 is an equidigital number, since it uses as much as digits as its factorization.

131021131027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 131021131027 its reverse (720131120131), we get a palindrome (851152251158).

The spelling of 131021131027 in words is "one hundred thirty-one billion, twenty-one million, one hundred thirty-one thousand, twenty-seven".