13102113133321 has 4 divisors (see below), whose sum is σ = 13297667060752. Its totient is φ = 12906559205892.

The previous prime is 13102113133289. The next prime is 13102113133381. The reversal of 13102113133321 is 12333131120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13102113133321 - 2⁵ = 13102113133289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102113133381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97776963615 + ... + 97776963748.

It is an arithmetic number, because the mean of its divisors is an integer number (3324416765188).

Almost surely, 2^{13102113133321} is an apocalyptic number.

It is an amenable number.

13102113133321 is a deficient number, since it is larger than the sum of its proper divisors (195553927431).

13102113133321 is an equidigital number, since it uses as much as digits as its factorization.

13102113133321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 195553927430.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13102113133321 its reverse (12333131120131), we get a palindrome (25435244253452).

The spelling of 13102113133321 in words is "thirteen trillion, one hundred two billion, one hundred thirteen million, one hundred thirty-three thousand, three hundred twenty-one".