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131021210032 = 248188825627
BaseRepresentation
bin111101000000101111…
…0010000000110110000
3110112012002112002102121
41322001132100012300
54121312412210112
6140105035124024
712315553624036
oct1720136200660
9415162462377
10131021210032
115062506a369
12214868a3614
13c480629b1b
1464acd78556
15361c834407
hex1e817901b0

131021210032 has 10 divisors (see below), whose sum is σ = 253853594468. Its totient is φ = 65510605008.

The previous prime is 131021210009. The next prime is 131021210039. The reversal of 131021210032 is 230012120131.

It is a Harshad number since it is a multiple of its sum of digits (16), and also a Moran number because the ratio is a prime number: 8188825627 = 131021210032 / (1 + 3 + 1 + 0 + 2 + 1 + 2 + 1 + 0 + 0 + 3 + 2).

It is a junction number, because it is equal to n+sod(n) for n = 131021209988 and 131021210015.

It is not an unprimeable number, because it can be changed into a prime (131021210039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4094412798 + ... + 4094412829.

Almost surely, 2131021210032 is an apocalyptic number.

It is an amenable number.

131021210032 is a deficient number, since it is larger than the sum of its proper divisors (122832384436).

131021210032 is an equidigital number, since it uses as much as digits as its factorization.

131021210032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8188825635 (or 8188825629 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 131021210032 its reverse (230012120131), we get a palindrome (361033330163).

The spelling of 131021210032 in words is "one hundred thirty-one billion, twenty-one million, two hundred ten thousand, thirty-two".

Divisors: 1 2 4 8 16 8188825627 16377651254 32755302508 65510605016 131021210032