Base | Representation |
---|---|
bin | 11000011001111001… |
… | …01010001101010100 |
3 | 1020211002222011111020 |
4 | 30030330222031110 |
5 | 203313121130004 |
6 | 10004040041140 |
7 | 642453160515 |
oct | 141474521524 |
9 | 36732864436 |
10 | 13102130004 |
11 | 56138a1217 |
12 | 2657a631b0 |
13 | 130a5acb62 |
14 | 8c4152a0c |
15 | 51a3c78d9 |
hex | 30cf2a354 |
13102130004 has 48 divisors (see below), whose sum is σ = 30957814272. Its totient is φ = 4312269792.
The previous prime is 13102129979. The next prime is 13102130011. The reversal of 13102130004 is 40003120131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2669817 + ... + 2674719.
It is an arithmetic number, because the mean of its divisors is an integer number (644954464).
Almost surely, 213102130004 is an apocalyptic number.
It is an amenable number.
13102130004 is an abundant number, since it is smaller than the sum of its proper divisors (17855684268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102130004 is a wasteful number, since it uses less digits than its factorization.
13102130004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7676 (or 7674 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 13102130004 its reverse (40003120131), we get a palindrome (53105250135).
The spelling of 13102130004 in words is "thirteen billion, one hundred two million, one hundred thirty thousand, four".
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