Base | Representation |
---|---|
bin | 11000011001111001… |
… | …01010001101100001 |
3 | 1020211002222011111201 |
4 | 30030330222031201 |
5 | 203313121130032 |
6 | 10004040041201 |
7 | 642453160534 |
oct | 141474521541 |
9 | 36732864451 |
10 | 13102130017 |
11 | 56138a1229 |
12 | 2657a63201 |
13 | 130a5acb72 |
14 | 8c4152a1b |
15 | 51a3c78e7 |
hex | 30cf2a361 |
13102130017 has 2 divisors, whose sum is σ = 13102130018. Its totient is φ = 13102130016.
The previous prime is 13102130011. The next prime is 13102130071. The reversal of 13102130017 is 71003120131.
Together with next prime (13102130071) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12462596496 + 639533521 = 111636^2 + 25289^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102130017 - 219 = 13101605729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102129976 and 13102130003.
It is not a weakly prime, because it can be changed into another prime (13102130011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551065008 + 6551065009.
It is an arithmetic number, because the mean of its divisors is an integer number (6551065009).
Almost surely, 213102130017 is an apocalyptic number.
It is an amenable number.
13102130017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102130017 is an equidigital number, since it uses as much as digits as its factorization.
13102130017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 19.
Adding to 13102130017 its reverse (71003120131), we get a palindrome (84105250148).
The spelling of 13102130017 in words is "thirteen billion, one hundred two million, one hundred thirty thousand, seventeen".
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