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13102130033 = 21162095403
BaseRepresentation
bin11000011001111001…
…01010001101110001
31020211002222011112022
430030330222031301
5203313121130113
610004040041225
7642453160556
oct141474521561
936732864468
1013102130033
1156138a1243
122657a63215
13130a5acb85
148c4152a2d
1551a3c7908
hex30cf2a371

13102130033 has 4 divisors (see below), whose sum is σ = 13164225648. Its totient is φ = 13040034420.

The previous prime is 13102130017. The next prime is 13102130071. The reversal of 13102130033 is 33003120131.

13102130033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13102130033 - 24 = 13102130017 is a prime.

It is a super-2 number, since 2×131021300332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13102129993 and 13102130020.

It is not an unprimeable number, because it can be changed into a prime (13102130533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31047491 + ... + 31047912.

It is an arithmetic number, because the mean of its divisors is an integer number (3291056412).

Almost surely, 213102130033 is an apocalyptic number.

It is an amenable number.

13102130033 is a deficient number, since it is larger than the sum of its proper divisors (62095615).

13102130033 is an equidigital number, since it uses as much as digits as its factorization.

13102130033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62095614.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13102130033 its reverse (33003120131), we get a palindrome (46105250164).

The spelling of 13102130033 in words is "thirteen billion, one hundred two million, one hundred thirty thousand, thirty-three".

Divisors: 1 211 62095403 13102130033