Base | Representation |
---|---|
bin | 11000011001111001… |
… | …01010001101110010 |
3 | 1020211002222011112100 |
4 | 30030330222031302 |
5 | 203313121130114 |
6 | 10004040041230 |
7 | 642453160560 |
oct | 141474521562 |
9 | 36732864470 |
10 | 13102130034 |
11 | 56138a1244 |
12 | 2657a63216 |
13 | 130a5acb86 |
14 | 8c4152a30 |
15 | 51a3c7909 |
hex | 30cf2a372 |
13102130034 has 48 divisors (see below), whose sum is σ = 32459057280. Its totient is φ = 3741655680.
The previous prime is 13102130017. The next prime is 13102130071. The reversal of 13102130034 is 43003120131.
13102130034 is a `hidden beast` number, since 1 + 310 + 21 + 300 + 34 = 666.
13102130034 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131021300342 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13102129989 and 13102130016.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 248227 + ... + 296345.
It is an arithmetic number, because the mean of its divisors is an integer number (676230360).
Almost surely, 213102130034 is an apocalyptic number.
13102130034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13102130034 is an abundant number, since it is smaller than the sum of its proper divisors (19356927246).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102130034 is a wasteful number, since it uses less digits than its factorization.
13102130034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50295 (or 50292 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13102130034 its reverse (43003120131), we get a palindrome (56105250165).
The spelling of 13102130034 in words is "thirteen billion, one hundred two million, one hundred thirty thousand, thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •