Base | Representation |
---|---|
bin | 10011000100001110110… |
… | …010011010100101101011 |
3 | 11122020220000010211100011 |
4 | 103010032302122211223 |
5 | 132431304024404121 |
6 | 2441523102152351 |
7 | 163442205533434 |
oct | 23041662324553 |
9 | 4566800124304 |
10 | 1310213122411 |
11 | 465727172226 |
12 | 191b178826b7 |
13 | 96724cb4a3b |
14 | 475b3b4848b |
15 | 241358807e1 |
hex | 1310ec9a96b |
1310213122411 has 2 divisors, whose sum is σ = 1310213122412. Its totient is φ = 1310213122410.
The previous prime is 1310213122343. The next prime is 1310213122451. The reversal of 1310213122411 is 1142213120131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310213122411 - 233 = 1301623187819 is a prime.
It is a super-2 number, since 2×13102131224112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310213122451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655106561205 + 655106561206.
It is an arithmetic number, because the mean of its divisors is an integer number (655106561206).
Almost surely, 21310213122411 is an apocalyptic number.
1310213122411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310213122411 is an equidigital number, since it uses as much as digits as its factorization.
1310213122411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 1310213122411 its reverse (1142213120131), we get a palindrome (2452426242542).
The spelling of 1310213122411 in words is "one trillion, three hundred ten billion, two hundred thirteen million, one hundred twenty-two thousand, four hundred eleven".
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