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131022021110121 = 3343112852731361
BaseRepresentation
bin11101110010100111110001…
…000001101010100101101001
3122011220120201221001000101000
4131302213301001222211221
5114133131044401010441
61142354404025145213
736412012552620651
oct3562476101524551
9564816657030330
10131022021110121
11388251441a8089
1212840b4192b209
135815428b844ab
14244d6dd0bd361
1510232b420d2b6
hex7729f106a969

131022021110121 has 16 divisors (see below), whose sum is σ = 198620807197120. Its totient is φ = 85316664908160.

The previous prime is 131022021110111. The next prime is 131022021110159. The reversal of 131022021110121 is 121011120220131.

It is a happy number.

131022021110121 is a `hidden beast` number, since 1 + 310 + 2 + 20 + 211 + 1 + 0 + 121 = 666.

It is not a de Polignac number, because 131022021110121 - 211 = 131022021108073 is a prime.

It is a super-4 number, since 4×1310220211101214 (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131022021110094 and 131022021110103.

It is not an unprimeable number, because it can be changed into a prime (131022021110111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56426364520 + ... + 56426366841.

It is an arithmetic number, because the mean of its divisors is an integer number (12413800449820).

Almost surely, 2131022021110121 is an apocalyptic number.

It is an amenable number.

131022021110121 is a deficient number, since it is larger than the sum of its proper divisors (67598786086999).

131022021110121 is a wasteful number, since it uses less digits than its factorization.

131022021110121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112852731413 (or 112852731407 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 131022021110121 its reverse (121011120220131), we get a palindrome (252033141330252).

The spelling of 131022021110121 in words is "one hundred thirty-one trillion, twenty-two billion, twenty-one million, one hundred ten thousand, one hundred twenty-one".

Divisors: 1 3 9 27 43 129 387 1161 112852731361 338558194083 1015674582249 3047023746747 4852667448523 14558002345569 43674007036707 131022021110121